How to find the coefficient of x^5 in the Binomial expansion of (x+y)^7| Grade 12 math Ontario
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YouTubeWONDER DAARA MATHEMATICS ONLINE
How to find the coefficient of x^5 in the Binomial expansion of (x+y)^7| Grade 12 math Ontario
The coefficient of x^5 using the binomial theorem formula in the expansion of (x+y)^7 was found using the binomial theorem formula. The binomial theorem formula is very important when answering such short exam practice questions. How to do binomial expansion to find the coefficient of x^5 was the main theme of this maths tutorial on binomial ...
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AQA FM: Binomial Expansion Question: Find the first 3 terms in the expansion, in ascending powers of x, of: (3 - x/9)^6 Give the terms in their simplest form. Key exam skill: Use binomial coefficients and take the first 3 terms only. For power 6, the first three coefficients are: 1, 6, 15 So: (3 - x/9)^6 First term: 3^6 = 729 Second term: 6 x 3^5 x (-x/9) = -162x Third term: 15 x 3^4 x (x^2/81) = 15x^2 Final answer: 729 - 162x 15x^2 Save this for revision. Follow for more AQA Level 2 Further Mat
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